|TensorFlow 2 version||View source on GitHub|
Computes the sum of elements across dimensions of a SparseTensor. (deprecated arguments) (deprecated arguments)
`tf.sparse_reduce_sum`Compat aliases for migration
See Migration guide for more details.
tf.sparse.reduce_sum( sp_input, axis=None, keepdims=None, reduction_axes=None, keep_dims=None )
This Op takes a SparseTensor and is the sparse counterpart to
tf.reduce_sum(). In particular, this Op also returns a dense
instead of a sparse one.
sp_input along the dimensions given in
keepdims is true, the rank of the tensor is reduced by 1 for each entry in
keepdims is true, the reduced dimensions are retained
with length 1.
reduction_axes has no entries, all dimensions are reduced, and a tensor
with a single element is returned. Additionally, the axes can be negative,
similar to the indexing rules in Python.
# 'x' represents [[1, ?, 1] # [?, 1, ?]] # where ? is implicitly-zero. tf.sparse.reduce_sum(x) ==> 3 tf.sparse.reduce_sum(x, 0) ==> [1, 1, 1] tf.sparse.reduce_sum(x, 1) ==> [2, 1] # Can also use -1 as the axis. tf.sparse.reduce_sum(x, 1, keepdims=True) ==> [, ] tf.sparse.reduce_sum(x, [0, 1]) ==> 3
||The SparseTensor to reduce. Should have numeric type.|
The dimensions to reduce; list or scalar. If
||If true, retain reduced dimensions with length 1.|
Deprecated name of
Deprecated alias for
|The reduced Tensor.|