tf.math.logical_xor

Logical XOR function.

View aliases

Compat aliases for migration

See Migration guide for more details.

tf.compat.v1.logical_xor, tf.compat.v1.math.logical_xor

tf.math.logical_xor(
    x, y, name='LogicalXor'
)

x ^ y = (x | y) & ~(x & y)

Requires that x and y have the same shape or have broadcast-compatible shapes. For example, x and y can be:

• Two single elements of type bool
• One tf.Tensor of type bool and one single bool, where the result will be calculated by applying logical XOR with the single element to each element in the larger Tensor.
• Two tf.Tensor objects of type bool of the same shape. In this case, the result will be the element-wise logical XOR of the two input tensors.

Usage:

a = tf.constant([True])
b = tf.constant([False])
tf.math.logical_xor(a, b)
<tf.Tensor: shape=(1,), dtype=bool, numpy=array([ True])>

c = tf.constant([True])
x = tf.constant([False, True, True, False])
tf.math.logical_xor(c, x)
<tf.Tensor: shape=(4,), dtype=bool, numpy=array([ True, False, False,  True])>

y = tf.constant([False, False, True, True])
z = tf.constant([False, True, False, True])
tf.math.logical_xor(y, z)
<tf.Tensor: shape=(4,), dtype=bool, numpy=array([False,  True,  True, False])>

Args
x	A tf.Tensor type bool.
y	A tf.Tensor of type bool.
name	A name for the operation (optional).

Returns
A tf.Tensor of type bool with the same size as that of x or y.