tensorflow::ops::SegmentSum
#include <math_ops.h>
Computes the sum along segments of a tensor.
Summary
Read the section on segmentation for an explanation of segments.
Computes a tensor such that \(output_i = data_j\) where sum is over j
such that segment_ids[j] == i
.
If the sum is empty for a given segment ID i
, output[i] = 0
.
For example:
c = tf.constant([[1,2,3,4], [4, 3, 2, 1], [5,6,7,8]]) tf.segment_sum(c, tf.constant([0, 0, 1])) # ==> [[5, 5, 5, 5], # [5, 6, 7, 8]]
Arguments:
- scope: A Scope object
- segment_ids: A 1-D tensor whose size is equal to the size of
data
's first dimension. Values should be sorted and can be repeated.
Returns:
Output
: Has same shape as data, except for dimension 0 which has sizek
, the number of segments.
Constructors and Destructors |
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SegmentSum(const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids)
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Public functions |
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node() const
|
::tensorflow::Node *
|
operator::tensorflow::Input() const
|
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operator::tensorflow::Output() const
|
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Public attributes
operation
Operation operation
output
::tensorflow::Output output
Public functions
SegmentSum
SegmentSum( const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids )
node
::tensorflow::Node * node() const
operator::tensorflow::Input
operator::tensorflow::Input() const
operator::tensorflow::Output
operator::tensorflow::Output() const