tensorflow::ops::SegmentSum

#include <math_ops.h>

Computes the sum along segments of a tensor.

Summary

Read the section on segmentation for an explanation of segments.

Computes a tensor such that \(output_i = \sum_j data_j\) where sum is over j such that segment_ids[j] == i.

If the sum is empty for a given segment ID i, output[i] = 0.

For example:

c = tf.constant([[1,2,3,4], [4, 3, 2, 1], [5,6,7,8]])
tf.segment_sum(c, tf.constant([0, 0, 1]))
# ==> [[5, 5, 5, 5],
#      [5, 6, 7, 8]]

Args:

scope: A Scope object
segment_ids: A 1-D tensor whose size is equal to the size of data's first dimension. Values should be sorted and can be repeated.

Returns:

Output: Has same shape as data, except for dimension 0 which has size k, the number of segments.

Constructors and Destructors
`SegmentSum(const ::tensorflow::Scope & scope, ::tensorflow::Input data, ::tensorflow::Input segment_ids)`

Public attributes
`operation`	`Operation`
`output`	`::tensorflow::Output`

Public functions
`node() const`	`::tensorflow::Node *`
`operator::tensorflow::Input() const`
`operator::tensorflow::Output() const`

Operation operation

::tensorflow::Output output

 SegmentSum(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input data,
  ::tensorflow::Input segment_ids
)

::tensorflow::Node * node() const

 operator::tensorflow::Input() const

 operator::tensorflow::Output() const