tf.math.reduce_sum
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Computes the sum of elements across dimensions of a tensor.
tf.math.reduce_sum(
input_tensor, axis=None, keepdims=False, name=None
)
Reduces input_tensor
along the dimensions given in axis
.
Unless keepdims
is true, the rank of the tensor is reduced by 1 for each
entry in axis
. If keepdims
is true, the reduced dimensions
are retained with length 1.
If axis
is None, all dimensions are reduced, and a
tensor with a single element is returned.
For example:
x = tf.constant([[1, 1, 1], [1, 1, 1]])
tf.reduce_sum(x) # 6
tf.reduce_sum(x, 0) # [2, 2, 2]
tf.reduce_sum(x, 1) # [3, 3]
tf.reduce_sum(x, 1, keepdims=True) # [[3], [3]]
tf.reduce_sum(x, [0, 1]) # 6
Args |
input_tensor
|
The tensor to reduce. Should have numeric type.
|
axis
|
The dimensions to reduce. If None (the default), reduces all
dimensions. Must be in the range [-rank(input_tensor),
rank(input_tensor)) .
|
keepdims
|
If true, retains reduced dimensions with length 1.
|
name
|
A name for the operation (optional).
|
Returns |
The reduced tensor, of the same dtype as the input_tensor.
|
Numpy Compatibility
Equivalent to np.sum apart the fact that numpy upcast uint8 and int32 to
int64 while tensorflow returns the same dtype as the input.
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Last updated 2020-10-01 UTC.
[null,null,["Last updated 2020-10-01 UTC."],[],[],null,["# tf.math.reduce_sum\n\n\u003cbr /\u003e\n\n|----------------------------------------------------------------------------|-----------------------------------------------------------------------------------------------------------------------------|\n| [TensorFlow 1 version](/versions/r1.15/api_docs/python/tf/math/reduce_sum) | [View source on GitHub](https://github.com/tensorflow/tensorflow/blob/v2.1.0/tensorflow/python/ops/math_ops.py#L1553-L1595) |\n\nComputes the sum of elements across dimensions of a tensor.\n\n#### View aliases\n\n\n**Main aliases**\n\n[`tf.reduce_sum`](/api_docs/python/tf/math/reduce_sum)\n\n\u003cbr /\u003e\n\n tf.math.reduce_sum(\n input_tensor, axis=None, keepdims=False, name=None\n )\n\nReduces `input_tensor` along the dimensions given in `axis`.\nUnless `keepdims` is true, the rank of the tensor is reduced by 1 for each\nentry in `axis`. If `keepdims` is true, the reduced dimensions\nare retained with length 1.\n\nIf `axis` is None, all dimensions are reduced, and a\ntensor with a single element is returned.\n\n#### For example:\n\n x = tf.constant([[1, 1, 1], [1, 1, 1]])\n tf.reduce_sum(x) # 6\n tf.reduce_sum(x, 0) # [2, 2, 2]\n tf.reduce_sum(x, 1) # [3, 3]\n tf.reduce_sum(x, 1, keepdims=True) # [[3], [3]]\n tf.reduce_sum(x, [0, 1]) # 6\n\n\u003cbr /\u003e\n\n\u003cbr /\u003e\n\n\u003cbr /\u003e\n\n| Args ---- ||\n|----------------|----------------------------------------------------------------------------------------------------------------------------------------------|\n| `input_tensor` | The tensor to reduce. Should have numeric type. |\n| `axis` | The dimensions to reduce. If `None` (the default), reduces all dimensions. Must be in the range `[-rank(input_tensor), rank(input_tensor))`. |\n| `keepdims` | If true, retains reduced dimensions with length 1. |\n| `name` | A name for the operation (optional). |\n\n\u003cbr /\u003e\n\n\u003cbr /\u003e\n\n\u003cbr /\u003e\n\n\u003cbr /\u003e\n\n| Returns ------- ||\n|---|---|\n| The reduced tensor, of the same dtype as the input_tensor. ||\n\n\u003cbr /\u003e\n\n#### Numpy Compatibility\n\nEquivalent to np.sum apart the fact that numpy upcast uint8 and int32 to\nint64 while tensorflow returns the same dtype as the input."]]