|  TensorFlow 1 version |  View source on GitHub | 
Reshapes a SparseTensor to represent values in a new dense shape.
tf.sparse.reshape(
    sp_input, shape, name=None
)
This operation has the same semantics as reshape on the represented dense
tensor.  The indices of non-empty values in sp_input are recomputed based
on the new dense shape, and a new SparseTensor is returned containing the
new indices and new shape.  The order of non-empty values in sp_input is
unchanged.
If one component of shape is the special value -1, the size of that
dimension is computed so that the total dense size remains constant.  At
most one component of shape can be -1.  The number of dense elements
implied by shape must be the same as the number of dense elements
originally represented by sp_input.
For example, if sp_input has shape [2, 3, 6] and indices / values:
[0, 0, 0]: a
[0, 0, 1]: b
[0, 1, 0]: c
[1, 0, 0]: d
[1, 2, 3]: e
and shape is [9, -1], then the output will be a SparseTensor of
shape [9, 4] and indices / values:
[0, 0]: a
[0, 1]: b
[1, 2]: c
[4, 2]: d
[8, 1]: e
| Args | |
|---|---|
| sp_input | The input SparseTensor. | 
| shape | A 1-D (vector) int64 Tensorspecifying the new dense shape of the
representedSparseTensor. | 
| name | A name prefix for the returned tensors (optional) | 
| Returns | |
|---|---|
| A SparseTensorwith the same non-empty values but with indices calculated
by the new dense shape. | 
| Raises | |
|---|---|
| TypeError | If sp_inputis not aSparseTensor. | 
| ValueError | If argument shaperequests aSparseTensorwith a different
number of elements thansp_input. | 
| ValueError | If shapehas more than one inferred (== -1) dimension. |