Elementwise computes the bitwise OR of x and y.
tf.raw_ops.BitwiseOr(
    x, y, name=None
)
The result will have those bits set, that are set in x, y or both. The
computation is performed on the underlying representations of x and y.
For example:
import tensorflow as tf
from tensorflow.python.ops import bitwise_ops
dtype_list = [tf.int8, tf.int16, tf.int32, tf.int64,
              tf.uint8, tf.uint16, tf.uint32, tf.uint64]
for dtype in dtype_list:
  lhs = tf.constant([0, 5, 3, 14], dtype=dtype)
  rhs = tf.constant([5, 0, 7, 11], dtype=dtype)
  exp = tf.constant([5, 5, 7, 15], dtype=tf.float32)
  res = bitwise_ops.bitwise_or(lhs, rhs)
  tf.assert_equal(tf.cast(res,  tf.float32), exp)  # TRUE
| Args | |
|---|---|
| x | A Tensor. Must be one of the following types:int8,int16,int32,int64,uint8,uint16,uint32,uint64. | 
| y | A Tensor. Must have the same type asx. | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| A Tensor. Has the same type asx. |