|  TensorFlow 1 version |  View source on GitHub | 
Returns the element-wise sum of a list of tensors.
tf.math.accumulate_n(
    inputs, shape=None, tensor_dtype=None, name=None
)
Optionally, pass shape and tensor_dtype for shape and type checking,
otherwise, these are inferred.
accumulate_n performs the same operation as tf.math.add_n, but
does not wait for all of its inputs to be ready before beginning to sum.
This approach can save memory if inputs are ready at different times, since
minimum temporary storage is proportional to the output size rather than the
inputs' size.
accumulate_n is differentiable (but wasn't previous to TensorFlow 1.7).
For example:
a = tf.constant([[1, 2], [3, 4]])
b = tf.constant([[5, 0], [0, 6]])
tf.math.accumulate_n([a, b, a])  # [[7, 4], [6, 14]]
# Explicitly pass shape and type
tf.math.accumulate_n([a, b, a], shape=[2, 2], tensor_dtype=tf.int32)
                                                               # [[7,  4],
                                                               #  [6, 14]]
| Args | |
|---|---|
| inputs | A list of Tensorobjects, each with same shape and type. | 
| shape | Expected shape of elements of inputs(optional). Also controls the
output shape of this op, which may affect type inference in other ops. A
value ofNonemeans "infer the input shape from the shapes ininputs". | 
| tensor_dtype | Expected data type of inputs(optional). A value ofNonemeans "infer the input dtype frominputs[0]". | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| A Tensorof same shape and type as the elements ofinputs. | 
| Raises | |
|---|---|
| ValueError | If inputsdon't all have same shape and dtype or the shape
cannot be inferred. |