|  TensorFlow 1 version |  View source on GitHub | 
Computes the Euclidean norm of elements across dimensions of a tensor.
tf.math.reduce_euclidean_norm(
    input_tensor, axis=None, keepdims=False, name=None
)
Reduces input_tensor along the dimensions given in axis.
Unless keepdims is true, the rank of the tensor is reduced by 1 for each
entry in axis. If keepdims is true, the reduced dimensions
are retained with length 1.
If axis is None, all dimensions are reduced, and a
tensor with a single element is returned.
For example:
x = tf.constant([[1, 2, 3], [1, 1, 1]])
tf.reduce_euclidean_norm(x)  # sqrt(17)
tf.reduce_euclidean_norm(x, 0)  # [sqrt(2), sqrt(5), sqrt(10)]
tf.reduce_euclidean_norm(x, 1)  # [sqrt(14), sqrt(3)]
tf.reduce_euclidean_norm(x, 1, keepdims=True)  # [[sqrt(14)], [sqrt(3)]]
tf.reduce_euclidean_norm(x, [0, 1])  # sqrt(17)
| Args | |
|---|---|
| input_tensor | The tensor to reduce. Should have numeric type. | 
| axis | The dimensions to reduce. If None(the default), reduces all
dimensions. Must be in the range[-rank(input_tensor),
rank(input_tensor)). | 
| keepdims | If true, retains reduced dimensions with length 1. | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| The reduced tensor, of the same dtype as the input_tensor. |