|  TensorFlow 1 version |  View source on GitHub | 
Computes the mean of elements across dimensions of a tensor.
tf.math.reduce_mean(
    input_tensor, axis=None, keepdims=False, name=None
)
Reduces input_tensor along the dimensions given in axis.
Unless keepdims is true, the rank of the tensor is reduced by 1 for each
entry in axis. If keepdims is true, the reduced dimensions
are retained with length 1.
If axis is None, all dimensions are reduced, and a
tensor with a single element is returned.
For example:
x = tf.constant([[1., 1.], [2., 2.]])
tf.reduce_mean(x)  # 1.5
tf.reduce_mean(x, 0)  # [1.5, 1.5]
tf.reduce_mean(x, 1)  # [1.,  2.]
| Args | |
|---|---|
| input_tensor | The tensor to reduce. Should have numeric type. | 
| axis | The dimensions to reduce. If None(the default), reduces all
dimensions. Must be in the range[-rank(input_tensor),
rank(input_tensor)). | 
| keepdims | If true, retains reduced dimensions with length 1. | 
| name | A name for the operation (optional). | 
| Returns | |
|---|---|
| The reduced tensor. | 
Numpy Compatibility
Equivalent to np.mean
Please note that np.mean has a dtype parameter that could be used to
specify the output type. By default this is dtype=float64. On the other
hand, tf.reduce_mean has an aggressive type inference from input_tensor,
for example:
x = tf.constant([1, 0, 1, 0])
tf.reduce_mean(x)  # 0
y = tf.constant([1., 0., 1., 0.])
tf.reduce_mean(y)  # 0.5