tf.truncatemod

TensorFlow 2 version

Returns element-wise remainder of division. This emulates C semantics in that

tf.truncatemod(
    x, y, name=None
)

the result here is consistent with a truncating divide. E.g. truncate(x / y) * y + truncate_mod(x, y) = x.

x A Tensor. Must be one of the following types: int32, int64, bfloat16, half, float32, float64.
y A Tensor. Must have the same type as x.
name A name for the operation (optional).

A Tensor. Has the same type as x.