Returns True
if x
is strictly increasing.
View aliases
Main aliases
`tf.debugging.is_strictly_increasing`, `tf.is_strictly_increasing`
Compat aliases for migrationSee Migration guide for more details.
tf.compat.v1.debugging.is_strictly_increasing
, tf.compat.v1.is_strictly_increasing
, tf.compat.v1.math.is_strictly_increasing
, `tf.compat.v2.math.is_strictly_increasing`
tf.math.is_strictly_increasing(
x, name=None
)
Elements of x
are compared in row-major order. The tensor [x[0],...]
is strictly increasing if for every adjacent pair we have x[i] < x[i+1]
.
If x
has less than two elements, it is trivially strictly increasing.
See also: is_non_decreasing
Args | |
---|---|
x
|
Numeric Tensor .
|
name
|
A name for this operation (optional). Defaults to "is_strictly_increasing" |
Returns | |
---|---|
Boolean Tensor , equal to True iff x is strictly increasing.
|
Raises | |
---|---|
TypeError
|
if x is not a numeric tensor.
|